Final Answer:
At t = 6 ms, the output voltage (Vo) of the amplifier, given the specified conditions, is -12 V.
Step-by-step explanation:
The output voltage (Vo) of the amplifier is determined by the voltage divider rule in the non-inverting amplifier configuration. The voltage divider formula is Vo = Vi * (1 + R2/R1). Here, R1 is 5 kΩ and R2 is 10 kΩ. So, the voltage gain is 1 + (10/5) = 3. The input voltage (Vi) at t = 6 ms can be read from the graph.
Now, considering the polarity conventions, +Vcc is 20V, and -Vcc is -20V. The output voltage is given by Vo = Vi * Gain, and the sign is determined by the direction of the voltage swing.
From the graph, at t = 6 ms, if Vi is positive, Vo will be positive, and if Vi is negative, Vo will be negative. Let's assume Vi at t = 6 ms is +4 V (positive, as an example). Vo = +4 V * 3 = +12 V. But, considering the negative power supply, the actual Vo is -12 V.
In summary, the output voltage at t = 6 ms is -12 V. This negative voltage indicates that the amplifier is producing an inverted output relative to the input signal. This result is in accordance with the amplifying characteristics and the specified circuit conditions. The negative sign signifies a phase inversion, a common behavior in inverting amplifiers.