Final answer:
The phasor quantities of the current in a series circuit with resistance and inductance are calculated using impedance and the phase angle, considering the inductive circuit's tendency for the current to lag the voltage.
Step-by-step explanation:
To find the phasor quantities of the current when a voltage is applied to a series circuit with a resistance (R) of 50 ohms and an inductance (L) of 0.03 H, one can use Ohm's law and the concept of impedance in an AC circuit. The impedance (Z) of the circuit is given by the formula Z = √(R^2 + (XL)^2), where XL is the inductive reactance. The inductive reactance can be calculated using XL = 2πfL, where f is the frequency of the AC source. Once the impedance is known, the current I can be calculated using the RMS voltage (Vrms) of the source divided by Z. The phasor of the current is then given by I = Vrms/Z at the angle of -θ, where θ is the phase angle between the voltage and the current. In a purely inductive circuit, the current would lag the voltage by 90 degrees, but in a series RL circuit, the phase angle is less than 90 degrees because of the resistance.