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A boost converter has an output of 30 V from 12 V source input during the Continuous Conduction Mode with the inductor, L=120μH, load resistance, 50Ω, and the switching frequency,fₛ=25kHz.

Draw the inductor current at least two switching periods.

User HeberLZ
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1 Answer

5 votes

Final answer:

The inductor current in a boost converter operating in the Continuous Conduction Mode follows a triangular waveform. It ramps up during the ON time of the switch and ramps down during the OFF time, as shown in a two-switching-period diagram.

Step-by-step explanation:

In a boost converter operating in the Continuous Conduction Mode, the inductor current follows a triangular waveform. The inductor current ramps up during the ON time of the switch and ramps down during the OFF time. Let's draw the inductor current for two switching periods:

Switching period 1: During the ON time, the inductor current ramps up linearly from 0A to a maximum value determined by the input voltage, output voltage, inductance, and load resistance. During the OFF time, the inductor current ramps down linearly back to 0A.

Switching period 2: The same pattern repeats, with the inductor current ramping up during the ON time and ramping down during the OFF time.

User Sergei Tachenov
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8.4k points
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