Question

A picce of a lossless RG-59B/U Coaxial cable has a nominal capacitance of 0.8pF/ meter, and inductance is 15nH/m. If the diameter of the inner conductor as 0.8 m, and the dielectric constant of the insulation is 4 then find the diameter of the outer conductor in cm?

Answer 1

To find the diameter of the outer conductor of the RG-59B/U coaxial cable, you can use the formula for capacitance per unit length of a coaxial cable. Plug in the given values and solve for the diameter of the outer conductor.

Step-by-step explanation:

To find the diameter of the outer conductor of the RG-59B/U coaxial cable, we need to use the formula for the capacitance per unit length of a coaxial cable. In this case, the capacitance per unit length is given by:

C = ((2πε₀εr)/(ln(b/a)) * (1/2π) * (1/L))

Where ε₀ is the permittivity of free space, εr is the relative permittivity of the insulation, b is the outer radius of the conductor, a is the inner radius of the conductor, and L is the inductance per unit length of the cable.

Plugging in the given values:

0.8 pF/m = ((2πε₀*4)/(ln(b/0.8)) * (1/2π) * (1/15 nH/m))

Simplifying the equation, we find:

b/0.8 = ((2πε₀*4)/(0.8 pF/m * 2π * 1/15 nH/m ))

And solving for b, we get:

b = 0.8 * ((2πε₀*4)/(0.8 pF/m * 2π * 1/15 nH/m ))

Therefore, the diameter of the outer conductor is 0.8 times the calculated value of b in cm.