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33 votes
A car has a velocity of 49.29 m/s. It then accelerates at a uniform rate of -4.00 m/s² for the next 5.40 seconds. what distance does it travel?

User Bumble
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1 Answer

21 votes
21 votes

\begin{gathered} v_o=49.29\text{ m/s} \\ a=-4.00m/s^2 \\ t=5.40\text{ s} \\ x_o=0\text{ m} \\ x_f=? \\ x_f=x_o+v_ot+(at^2)/(2) \\ x_f=0\text{ m+}(49.29\text{ m/s})(5.40\text{ s})+\frac{(-4.00m/s^2)(5.40\text{ s})^2}{2} \\ x_f=\text{207}.85m \\ It\text{ travels 207.85 m} \end{gathered}

User Adekemi
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