Final answer:
The student is asking to create a circuit for a synchronous counter using JK flip flops with a counting sequence of 0,1,2,3. We need two JK flip flops with the outputs connected to produce a binary count. The J and K inputs of the first flip flop are always high, while the J and K of the second are connected to the output of the first flip flop.
Step-by-step explanation:
The student is asking about designing a synchronous counter using JK flip flops that follows a counting sequence of 0,1,2,3, and then repeats. The sequence (0,1,2,3) can be represented in binary as (00, 01, 10, 11). Given that it is a 2-bit counter, we need two flip flops. The simplest approach for a mod-4 counter is to connect the output of the first flip flop (Q0) to the clock input of the second flip flop. As we're dealing with JK flip flops, the J and K inputs would generally be connected to HIGH (logic 1), as JK flip-flops toggle their output when both J and K inputs are high upon receiving a clock pulse.
To design this counter, we will enforce that the outputs Q0 and Q1 correspond to the binary digits (LSB and MSB, respectively). At each clock pulse, Q0 should toggle, so J0 and K0 are connected to HIGH. As for Q1, it should toggle only when Q0 is HIGH (binary 1), so we can connect J1 and K1 to the output of Q0. This ensures that Q1 changes state only when Q0 has transitioned from HIGH to LOW, resulting in the appropriate counting sequence.