Final answer:
The total current in the series circuit with resistors of 11.83 ohms, 17.31 ohms, and 17.21 ohms connected to an 88.90 volt battery is approximately 1.92 A.
Step-by-step explanation:
The current running through a series circuit consisting of a 11.83 ohm resistor, a 17.31 ohm resistor, and a 17.21 ohm resistor connected to an 88.90 volt battery can be calculated using Ohm's Law, which states I = V / R, where I is the current, V is the voltage, and R is the total resistance. In a series circuit, the total resistance is the sum of all resistances. Thus, the equivalent resistance of this circuit is 11.83 Ω + 17.31 Ω + 17.21 Ω = 46.35 Ω. The total current in the circuit is therefore I = V / R = 88.90 V / 46.35 Ω which equals approximately 1.92 A.