Final answer:
The inverse discrete time Fourier transform of H(jΩ) = { 1, |Ω| > Ωc 0 is h[k] = (1/2πjk) (cos(πk) + jsin(πk) - e⁽ʲΩᵏ⁾)
Step-by-step explanation:
To calculate the inverse discrete-time Fourier transform (I D T F `T) of H(jΩ), we need to determine the impulse response h[k] of the ideal high pass filter.
The given transfer function H(jΩ) is defined as follows:
H(jΩ) = { 1, |Ω| > Ωc 0, elsewhere
To find the impulse response h[k], we will use the inverse Fourier transform:
1. Start with the definition of the inverse Fourier transform:
h[k] = (1/2π) ∫[−π,π] H(jΩ) e⁽ʲΩᵏ⁾ dΩ
2. Split the integral into two parts based on the given condition for H(jΩ):
h[k] = (1/2π) ∫[−π,−Ωc] 0 e⁽ʲΩᵏ⁾) dΩ + (1/2π) ∫[Ωc,π] 1 e⁽ʲΩᵏ⁾ dΩ
3. Evaluate the integrals:
h[k] = (1/2π) ∫[−π,−Ωc] 0 dΩ + (1/2π) ∫[Ωc,π] e⁽ʲΩᵏ⁾) dΩ
The first integral is zero, so we only need to calculate the second integral.
4. Solve the second integral:
h[k] = (1/2π) ∫[Ωc,π] e⁽ʲΩᵏ⁾) dΩ
Let's substitute u = jΩk, then dΩ = du/(jk).
h[k] = (1/2π) ∫[Ωc,π] eᵘ du/(jk)
5. Simplify the expression:
- h[k] = (1/2πjk) eᵘ ∣ [Ωc,π]
- h[k] = (1/2πjk) (e⁽ʲΩᵏ⁾ ∣ [Ωc,π])
- h[k] = (1/2πjk) (e⁽ʲπᵏ⁾ - e⁽ʲΩᵏ⁾)
6. Finally, simplify further:
h[k] = (1/2πjk) (cos(πk) + jsin(πk) - e⁽ʲΩᵏ⁾)
The above equation represents the impulse response h[k] of the ideal highpass filter.