Question

Specify the Nyquist rate and the Nyquist interval for the signal g(t)=sinc²(400t). Problem 2. Consider sampling of the sinusoidal wave g(t)=sin(πt). Determine the Fourier transform of the instantaneous sampled signal for the following sampling periods and draw the magnitude spectrum:

Ts​=0.25 second;

Answer 1

The Nyquist rate for the signal g(t) = sinc²(400t) is 800 Hz and the Nyquist interval is 1.25 ms.

Step-by-step explanation:

The Nyquist rate and Nyquist interval are concepts related to sampling a signal. The Nyquist rate is defined as twice the highest frequency component present in the signal. In this case, the signal is g(t) = sinc²(400t), which has a maximum frequency of 400 Hz. Therefore, the Nyquist rate would be 2 * 400 = 800 Hz. The Nyquist interval is the time between each sample, which can be calculated by taking the inverse of the Nyquist rate. In this case, the Nyquist interval would be 1/800s, or 1.25 ms.