Final answer:
The capacitance required to attain resonance in the circuit is 3.18 μF.
Step-by-step explanation:
To calculate the capacitance required to attain resonance in the given circuit, we need to use the formula for resonant frequency:
fr = 1 / (2π√(LC))
Given values: Resistance (R) = 4.0 Ω, Inductance (L) = 0.5 H. We need to find the capacitance (C).
Substituting these values in the formula, we have:
50 = 1 / (2π√(0.5C))
Simplifying the equation and solving for C:
C = (1 / (4π² × L × f²)) = (1 / (4π² × 0.5 × 50²)) = 3.18 μF
Therefore, the required capacitance to attain resonance in the circuit is 3.18 μF.