Question

Include fprintf in exercise 6 to print the roots of the quadratic equations with the following message:

Roots of the quadratic equation Ax² +Bx+C = 0 are Root #1 & Root # 2
where Root # 1 and Root # 2 are the first and second calculated roots of the quadratic equation.
Sample Output
Enter the cofficients of a quadratic equation in a vector form: [1 5 10]
Roots of the quadratic equation 1x² + 5x + 10 = 0 are -2.50+j1.94 and -2.50-j1.94
NOTE: Complex numbers cannot be printed with a single specifier (%).

Answer 1

To solve for the roots of a quadratic equation, we apply the quadratic formula. For complex roots, each part of the complex number must be printed separately since a single format specifier cannot be used for complex numbers.

Step-by-step explanation:

To find the roots of a quadratic equation of the form ax²+bx+c = 0, we use the quadratic formula x = (-b ± √(b²-4ac))/(2a). This formula allows us to calculate the solutions for x, which are the points where the quadratic function intersects the x-axis or the roots of the equation.

For the equation 1x² + 5x + 10 = 0, substituting a = 1, b = 5, and c = 10 into the formula yields two complex roots. Since complex numbers are involved, it's important to represent the real and imaginary parts separately when printing. For instance, the roots can be printed using fprintf in the following format: Roots of the quadratic equation 1x² + 5x + 10 = 0 are -2.50+j1.94 and -2.50-j1.94, where 'j' denotes the imaginary unit.