Question

The voltage drop across the emitter and the base ( VBE​) in npn transistor is 0.7 at a collector current of 350μA. Find the collector current when VBE​ increases to 0.75 V. Find the VBE​ when ic=10μA.

Answer 1

Without additional parameters, it's impossible to calculate the exact new collector current when VBE increases to 0.75 V or to find VBE for a collector current of 10μA.

Step-by-step explanation:

The voltage drop across the emitter and base of an NPN transistor, also known as VBE, is pivotal in determining the collector current (IC). A change in VBE affects the collector current due to the transistor's property of allowing current flow from the emitter to the collector, controlled by the base voltage, as described in Figure 9.26. However, without additional information such as the transistor parameters or the relationship between VBE and IC (for example, the temperature voltage coefficient or beta value), it's impossible to calculate a precise new collector current when VBE increases to 0.75 V. Similarly, without these parameters, we cannot determine the base-emitter voltage VBE when the collector current IC is 10μA.