Final answer:
In a single-phase AC circuit, the complex power S is given by the formula S = P + jQ, where P is the real power and Q is the reactive power. Given that the load draws 10 kW at a power factor of 0.9 lagging, we can calculate the real power as P = 10 kW * 0.9 = 9 kW. Since the load is purely resistive, the reactive power is zero, so Q = 0. Therefore, the complex power S = 9 kW + j0.
Step-by-step explanation:
In a single-phase AC circuit, the complex power S is given by the formula S = P + jQ, where P is the real power and Q is the reactive power.
Given that the load draws 10 kW at a power factor of 0.9 lagging, we can calculate the real power as P = 10 kW * 0.9 = 9 kW.
Since the load is purely resistive, the reactive power is zero, so Q = 0. Therefore, the complex power S = 9 kW + j0.