Question

Let's suppose you design a cable TV network operating at 1.3μm where each channel carries 100Mb/s broadcast data. The receiver end is constructed by using a p−i−n diode with 60MHz noise bandwidth, 0.75 A/W responsivity and 100ohm load impedance. Detector is followed with an RF amplifier with 3 dB noise figure. Calculate the minimum power required to achieve 10⁻⁹ BER ? If you want to increase the BER to 10⁻¹², how much additional power is required? (Dark current can be ignored)

Answer 1

To calculate the minimum power and additional power required to achieve different bit error rates in a cable TV network.

Step-by-step explanation:

To calculate the minimum power required to achieve a 10-9 BER (bit error rate), we can use the formula:

Minimum Power = -10log10(BER) / Responsivity * Bandwidth * Load Impedance

where Responsivity is given as 0.75 A/W, Bandwidth is given as 60 MHz, and Load Impedance is given as 100 ohms. Calculate the minimum power using these values, and then to find the additional power required to achieve a 10-12 BER, we can use the formula:

Additional Power = -10log10(New BER / Old BER) / Responsivity * Bandwidth * Load Impedance

where New BER is 10-12 and Old BER is 10-9. Calculate the additional power using these values.