103k views
5 votes
What is the phase in degrees of the current through a 20-mH inductor when the applied voltage across its terminals is v(t) 48 cos(377t 20") V? Hint: Provide only the numerical answer in decimal format. Answer:

User Kranu
by
8.6k points

1 Answer

1 vote

Final answer:

The phase of the current through the inductor is -110°, which can also be represented as 250° since both are equivalent.

Step-by-step explanation:

The phase of the current through a 20-mH inductor when the applied voltage is v(t) = 48 cos(377t - 20°) V is determined by the fact that in an AC circuit, the voltage across an inductor leads the current by 90°. Therefore, if the voltage has a phase of -20° (as given), the current will lag this voltage phase by 90°. To find the phase of the current, subtract 90° from the voltage phase, resulting in a current phase of -20° - 90° = -110°. However, this angle can be usually expressed in a range from 0° to 360°, in which case the phase can also be given as 250°. Both answers are equivalent and the choice between them depends on the specific context of the problem.

User Hemendra Sharma
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.