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HELP MATH HELP MATH math is hard pls help me and give workings too thank you so much

HELP MATH HELP MATH math is hard pls help me and give workings too thank you so much-example-1

2 Answers

7 votes

Answer:

For the first question the answer is 50(0.2 + 1)^2 = 72

For the second question it is y = 32

Explanation:

In case you need to see how i got it...it's below

For number 1, y is proportional to (x + 1)^2

The equation would be y(x +1)^2 = k(the constant). Then I substituted numbers you gave me in the equation which was : 50(0.2 + 1)^2 = k(72)

For number 2 I used this equation: y (x + 1)^2 = 72. I substituted x for 0.5. The equation will be: y(0.5 + 1)^2 = 72. Then I got 32 for y.

Hope this helps:)

Explanation:

User Andrei Shender
by
4.2k points
5 votes

Answer:

For the first question the answer is 50(0.2 + 1)^2 = 72

For the second question it is y = 32

Explanation:

In case you need to see how i got it...it's below

For number 1, y is proportional to (x + 1)^2

The equation would be y(x +1)^2 = k(the constant). Then I substituted numbers you gave me in the equation which was : 50(0.2 + 1)^2 = k(72)

For number 2 I used this equation: y (x + 1)^2 = 72. I substituted x for 0.5. The equation will be: y(0.5 + 1)^2 = 72. Then I got 32 for y.

Hope this helps:)

User Teru
by
4.2k points