Final answer:
The convolution y[n] of x[n] and h[n] is calculated by summing the product of overlapping elements for each shift in the range of n from 1 to 12.
Step-by-step explanation:
The convolution of two discrete-time signals x[n] and h[n] is performed by sliding one signal past the other and calculating the area of overlap for each shift. Given x[n] is non-zero from 1 to 8 and h[n] is non-zero from 0 to 4, we can compute the convolution y[n] by considering all possible overlaps between these two signals.
Steps for computing y[n]:
- Determine the range of n for which y[n] will be non-zero. In this case, it's from n=1 to n=12. This is because the earliest point of non-zero overlap occurs at n=1 (the first point of x[n] with h[0]) and the latest point of non-zero overlap occurs when h[4] crosses the last point of x[n] at n=8+4=12.
- For each n in the determined range, sum the product of x[k] and h[n-k], where k ranges over all the values that produce non-zero products.
- Display the results in a list or sequence that provides the value of y[n] for each n.