Question

A steady-flow adiabatic compressor is used to compress 0.15 kg/s of air from 150kPa and 35℃ to a final pressure 1.5MPa and 595 K. Calculate the work required. Assume Cp=1.005 kJ/kg−K. As a design engineer you are asked to verify such an operation of the compressor is internally reversible, irreversible or impossible Drawschematic and TSdiagrams and label it. Neglect KE and PE changes.

Answer 1

The work required to compress the air can be calculated using the first law of thermodynamics, and is equal to 85.54 kJ/s.

Step-by-step explanation:

In order to calculate the work required, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. Since the process is adiabatic, there is no heat transfer, so the change in internal energy is equal to the work done by the compressor.

The work done by the compressor can be calculated using the equation W = m * Cp * (T2 - T1), where W is the work done, m is the mass flow rate of the air, Cp is the specific heat capacity at constant pressure, and T2 and T1 are the final and initial temperatures, respectively.

Plugging in the given values, we have W = 0.15 kg/s * 1.005 kJ/kg-K * (595 K - 35 K) = 85.54 kJ/s.