Final answer:
When two capacitors are connected in series, the total capacitance is given by the reciprocal of the sum of the reciprocals of the individual capacitances. The potential difference across the plates of each capacitor remains the same when they are connected in series.
Step-by-step explanation:
When two capacitors are connected in series, the total capacitance is given by the reciprocal of the sum of the reciprocals of the individual capacitances. Therefore, for two capacitors connected in series with capacitances C1 and C2, the total capacitance is given by:
C_total = 1 / (1/C1 + 1/C2)
In this case, the two capacitors have capacitances of 19 μF and 62 μF. Plugging these values into the formula, we can determine the total capacitance after the connection is made.
The potential difference across the plates of each capacitor remains the same when they are connected in series. Therefore, the potential difference across both capacitors is equal to the potential difference of the source, which is 100 V.