Question

A 75Ω coaxial line has a current

i(t,z) = 1.8 cos (3.77 × 10⁹ t−18.13z) mA.
Determine (a) the frequency, (b) the phase velocity, (c) the wavelength, (d) the relative permittivity of the line, (e) the phasor form of the current, and (f) the time domain voltage on the line.

Answer 1

The amplitude of the current is 1.8 mA, the frequency is 3.77 × 10^9 Hz, and the phasor form of the current is represented by 1.8 mA.

Step-by-step explanation:

(a) The amplitude of the current is given as 1.8 mA.

(b) The frequency can be found by looking at the coefficient in front of 't' in the cosine function, which is 3.77 × 10^9 Hz.

(c) The wavelength can be determined using the formula v = λf, where v is the phase velocity and f is the frequency. However, the phase velocity is not given in the question, so it cannot be calculated.

(d) The relative permittivity of the line is not provided in the question.

(e) The phasor form of the current is represented by 1.8 mA.

(f) The time domain voltage on the line is not provided in the question.