Question

Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-fertilized. If

the capital letters represent dominant, independently assorting alleles. What proportion of the F2
genotypes will be recessive for all five loci?
A) 1/256
B) 1/1024
C) 1/16
D) 1/64
E) 1/243

Answer 1

The proportion of the F2 genotypes that will be homozygous recessive for all five loci in the given scenario is 1/1024, which is achieved by calculating the individual probabilities of each locus and multiplying them together.

Step-by-step explanation:

The question deals with the proportion of F2 genotypes that will be recessive for all five loci when AABBCCDDEE is mated with aabbccddee, and the resulting F1 is self-fertilized. Since all the given alleles assort independently and the proportion of receiving a recessive allele from an Aa individual (heterozygous) is 1/2, we need to consider the probability for all the five loci (A, B, C, D, and E). The probability for one locus to be homozygous recessive (aa) is (1/2) x (1/2) = 1/4 because the F1 offspring will be Aa and we need both a's for it to be recessive. For all five loci to be recessive (aaaaa), we multiply the individual locus probabilities: (1/4)5 = 1/1024. Therefore, the proportion of the F2 genotypes that will be recessive for all five loci is option B) 1/1024.