Final answer:
The student's question may be regarding two different chemical reactions involving C₂H₅Br and alcoholic KOH or the combustion of ethanol. The balanced equation for the combustion of ethanol is C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g). The reaction of ethyl bromide with alcoholic KOH typically forms an alkene and water, but the question lacks the necessary conditions to confirm the exact response.
Step-by-step explanation:
Chemical Reaction Equation Balance
The student appears to be asking for two separate balanced chemical equations. The first reaction involves ethyl bromide (C₂H₅Br) and alcoholic KOH, which typically undergoes a dehydrohalogenation reaction to form an alkene. However, the student also includes an equation for a different reaction:
C₂H₅OH(1) + O₂(g) → CO₂(g) + H₂O(g)
This is a combustion reaction where ethanol reacts with oxygen to produce carbon dioxide and water.
Unfortunately, due to the ambiguity in the student's question, we are uncertain whether they are asking about the first reaction or the second. To provide clarity, the balanced equation for the combustion of ethanol is:
C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)
This equation is balanced with 2 carbon atoms, 6 hydrogen atoms, and 7 oxygen atoms on both sides. With respect to ethyl bromide and alcoholic KOH, the expected reaction would result in an alkene (ethylene in this case) and water, with the balanced equation likely being:
C₂H₅Br(l) + KOH(aq) → C₂H₄(g) + KBr(aq) + H₂O(l)
However, this reaction only occurs with a strong base, and the conditions are not specified in the question.