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The inductance L in micro henrys of a coil constructed by a ham radio operator is equal to the product of the square of the coils radius and 10 times the coils length. set up this equation and solve for L if the radius is 2 inches, the number of turns of wire is 150 and the coils length is 7 inches.

a. 1,076.31
b. 1,056.41
c. 1,036.61
d. 1,046.51

1 Answer

4 votes

Final answer:

The inductance L of the coil, calculated using the provided formula and the given measurements for radius and length, is 2,800 microhenrys. This value does not match any of the options provided in the question.

Step-by-step explanation:

The inductance L in microhenrys for a coil used by a ham radio operator can be determined by the formula provided in the question. Given the radius r is 2 inches and the coil's length l is 7 inches, we can plug these values into the equation L = r2 × 10 × l. We are not given any dependence of the inductance on the number of turns of wire, so this information is irrelevant for this calculation.

To solve for L, we convert inches to microhenrys to ensure consistent units:

  • Radius r = 2 inches
  • Length l = 7 inches

Substitute these values into the equation:

L = (2 inches)2 × 10 × (7 inches)

L = 4 × 10 × 7

L = 280 × 10

L = 2,800 microhenrys

Therefore, the inductance L of the coil is 2,800 microhenrys, but since none of the options given (a: 1,076.31, b: 1,056.41, c: 1,036.61, d: 1,046.51) matches this value, there might be a misunderstanding in the question or a possible typo in the options provided.

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