9.6k views
3 votes
0.1 kg tennis ball is traveling west at 40 m/s. A racket hits the ball to the east with a force of 60 N. The racket and the ball are in contact for 0.15 s. How fast and what direction is the ball traveling after the hit?

User Orri
by
7.5k points

1 Answer

3 votes

The tennis ball is traveling east at 20 m/s after the hit.

When the racket hits the tennis ball, the ball experiences an impulse due to the force applied by the racket. Impulse is the product of force and the time over which it acts, given by the equation Impulse=F⋅Δt. In this scenario, the force applied by the racket is 60 N, and the contact time is 0.15 seconds.

The impulse causes a change in the ball's momentum, which is the product of its mass and velocity. The initial momentum of the tennis ball before the hit is given by Momentum initial​=mass×initial velocity. After the hit, the final momentum is Momentum final =mass×final velocity.

Applying the principle of conservation of linear momentum, which states that the total linear momentum of a system remains constant if no external forces act on it, we can set the initial momentum equal to the final momentum. Mathematically, this is expressed as Momentum initial​ =Momentum final.

Solving for the final velocity (v final), we find that the tennis ball is traveling east at 20 m/s after the hit. The change in direction from west to east is due to the application of force by the racket, causing the ball to reverse its original direction.

User Graham Griffiths
by
8.0k points