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Draw a force diagram for a ball at the top of a parabolic trajectory. Label the forces and use equality marks on the force vectors. Ignore air resistance. The mass of the ball is 2 kg.

User Naydichev
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At the top of a parabolic trajectory, only two forces acting on the ball are its weight (W) and the normal force (N) which are equal in magnitude and opposite in direction, resulting in a net force of zero.

At the top of a parabolic trajectory, the ball is not accelerating vertically, so the net force acting on it in the vertical direction is zero which means that the weight of the ball (W) is equal to the normal force (N).

The weight of the ball (W) can be calculated using the formula

Weight = mg, where m = the mass of the ball (2 kg)

g = acceleration due to gravity (9.81 m/s²).

W = 2 kg × 9.81 m/s²

= 19.62 N

The weight of the ball is equal to the normal force (N), then N = 19.62 N.

Draw a force diagram for a ball at the top of a parabolic trajectory. Label the forces-example-1
User NebulaSleuth
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