Final answer:
The question refers to the amount of carbon dioxide CO2, not C2, produced from the combustion of ethane with oxygen. By using stoichiometry, it's determined that 107 grams of CO2 are produced from 125 g of O2, with O2 as the limiting reactant. So the correct answer is Option B.
Step-by-step explanation:
The combustion of ethane (C2H6) with oxygen (O2) produces carbon dioxide (CO2) and water (H2O) and is represented by the balanced chemical equation:
2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)
To find out how many grams of C2 are produced, we first need to correct the question, assuming it asks for CO2 production from the combustion of ethane, since 'C2' as a diatomic carbon molecule is not a common product of combustion.
From the equation, we see that 2 moles of C2H6 will react with 7 moles of O2 to produce 4 moles of CO2. The molar mass of O2 is approximately 32.00 g/mol. Hence, 7 moles of O2 weigh 224 g (7 moles × 32.00 g/mol). This implies that 125 g of O2 is less than the required oxygen to react with the ethane, making oxygen the limiting reactant.
To find the amount of CO2 produced from 125 g of O2, we use stoichiometry:
(125 g O2 × (1 mole O2 / 32.00 g O2)) × (4 moles CO2 / 7 moles O2) × (44.01 g CO2 / 1 mole CO2) = 125 g × (1/32.00) × (4/7) × 44.01
Calculating the mass of CO2 produced, we get approximately 107 grams of CO2. Therefore, the correct answer is B) 107 grams.