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Find the area of the surface obtained by rotating the curve 25x = y² + 50 about x-axis from

x=2 to x = 7.

User Chrystyna
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Final answer:

The question asks for the surface area of a surface of revolution created by rotating the given curve around the x-axis. The equation of the curve is rearranged to solve for y, the derivative dy/dx is found, and the surface area formula is applied with integration from x=2 to x=7 to find the result.

Step-by-step explanation:

The student is asking about finding the area of a surface of revolution, generated by rotating a given curve about the x-axis. In this particular problem, the equation given is 25x = y² + 50, and the rotation is performed from x=2 to x=7. To calculate the surface area, we need to use the formula for the surface area of a surface of revolution, which, when rotating about the x-axis, is:

A = 2π ∫ y ∙ sqrt(1 + (dy/dx)²) dx

We first need to express y in terms of x, so rearrange the given equation as y = sqrt(25x - 50). We then find the derivative of y with respect to x, which is dy/dx = 25/(2sqrt(25x - 50)). Plugging this into our formula and integrating from x=2 to x=7 will give us the surface area.

It's essential to proceed with the integral computation to find the exact surface area.

User Mavnn
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