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If the pressure and Kelvin temperature of 2.00 moles of an ideal gas at STP are doubled, the resulting volume will be

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Final answer:

If the pressure and Kelvin temperature of a gas at STP are doubled, the resulting volume will remain the same.

Step-by-step explanation:

According to the combined gas law, V1/T1 = V2/T2, if the pressure and Kelvin temperature of 2.00 moles of an ideal gas at STP are doubled, the resulting volume will be:

V1 = V2, T1 = T2

Therefore, the equation becomes:

V2/2T2 = V2/T1

Simplifying the equation, we get:

2T2 = T1

So the temperature T2 is half of T1. Substitute back into the equation:

V2/2(T1/2) = V2/T1

Canceling out terms:

V2/T1 = V2/T1

Therefore, the resulting volume will remain the same when the pressure and temperature are doubled.

User BurmajaM
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