Final answer:
If the pressure and Kelvin temperature of a gas at STP are doubled, the resulting volume will remain the same.
Step-by-step explanation:
According to the combined gas law, V1/T1 = V2/T2, if the pressure and Kelvin temperature of 2.00 moles of an ideal gas at STP are doubled, the resulting volume will be:
V1 = V2, T1 = T2
Therefore, the equation becomes:
V2/2T2 = V2/T1
Simplifying the equation, we get:
2T2 = T1
So the temperature T2 is half of T1. Substitute back into the equation:
V2/2(T1/2) = V2/T1
Canceling out terms:
V2/T1 = V2/T1
Therefore, the resulting volume will remain the same when the pressure and temperature are doubled.