109k views
1 vote
Find the minimum value of the function f(x) = x² + 12.2x + 35.1 to the nearest
hundredth.

User Yglodt
by
7.8k points

1 Answer

0 votes

Final answer:

To find the minimum value of the function f(x) = x² + 12.2x + 35.1, we can use the vertex form of a quadratic function. The vertex form is given by f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola.

Step-by-step explanation:

To find the minimum value of the function f(x) = x² + 12.2x + 35.1, we can use the vertex form of a quadratic function. The vertex form is given by f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola.

In this case, a = 1, and the coefficient of x is positive. Therefore, the parabola opens upwards and the vertex represents the minimum value of the function.

To find the x-coordinate of the vertex, we can use the formula x = -b/(2a). Plugging in the values, we get x = -12.2/(2*1) = -6.1. Substituting this back into the original equation, we get f(-6.1) = (-6.1)² + 12.2(-6.1) + 35.1 = 19.81 - 74.42 + 35.1 = -19.51.

Therefore, the minimum value of the function is -19.51 to the nearest hundredth.

User Travis Troyer
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories