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Suppose that $63,000 is invested at 4 1/2 % interest, compounded quarterly.

a) Find the function for the amount to which the investment grows after t years.

1 Answer

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Final answer:

The function for the amount to which a $63,000 investment at 4 1/2% interest compounded quarterly grows after t years is A(t) = 63000(1 + 0.045/4)^(4t).

Step-by-step explanation:

To find the function for the amount to which the investment grows after t years with an initial investment of $63,000 at 4 1/2% interest compounded quarterly, we use the compound interest formula:

A(t) = P(1 + \frac{r}{n})^{nt}

Where:

  • A(t) is the amount of money accumulated after t years, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested for, in years.

Given:

  • P = $63,000
  • r = 4.5% or 0.045 (as a decimal)
  • n = 4 (since interest is compounded quarterly)

We substitute these values into the formula:

A(t) = 63000(1 + \frac{0.045}{4})^{4t}

This function can be used to calculate the future value of the $63,000 investment at any time t years in the future.

User Zeeshan Adnan
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