Question

If the weights of carbon, hydrogen, and oxygen are approximately 12g/mol, 1g/mol, and 16 g/mol respectively, about how much would 1 mole of sucrose (C₆H₁₂O₆) weigh?

Answer 1

1 mole of sucrose (C₁₂H₂₂O₁₁) would weigh approximately 342 grams. This is calculated by summing the molar masses of 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms based on the given weights of each element per mole.

Step-by-step explanation:

To calculate the weight of 1 mole of sucrose (C₁₂H₂₂O₁₁), we add together the molar masses of each element in the molecular formula. The molecular formula for sucrose tells us there are 12 carbons, 22 hydrogens, and 11 oxygens.

Using the provided atomic weights, we have:

• Carbon (C): 12 atoms × 12 g/mol = 144 g/mol
• Hydrogen (H): 22 atoms × 1 g/mol = 22 g/mol
• Oxygen (O): 11 atoms × 16 g/mol = 176 g/mol

Adding these amounts together gives us:

1 mole of sucrose (C₁₂H₂₂O₁₁) = 144 g/mol (C) + 22 g/mol (H) + 176 g/mol (O) = 342 g/mol.

Therefore, 1 mole of sucrose would weigh approximately 342 grams.