Question

If sin theta = 4/9, then what is the value of sin (π- theta)?

Answer 1

To answer this question, we need to use the inverse function of sin, that is, arcsin or sin^-1 to find the value of the angle for which sin(theta) = 4/9. Then, we have:

`\sin (\theta)=(4)/(9)\Rightarrow\arcsin (\sin (\theta))=\arcsin ((4)/(9))`

Then, we have:

`\theta=\arcsin ((4)/(9))\Rightarrow\theta=0.460553991681`

This angle is in radians. Now, we need to find the value for sin (pi - theta) as follows:

`\sin (\pi-0.460553991681)=0.44444444444\ldots`

Now, we know this periodical decimal expression is equal to: