Question

A professor assigns a 10 -page paper to his class. Student A is on page 5 and is writing 1/2 page each hour. Student B is on page 2 and is writing 1 page each hour. How many hours will it take for Student B to have the same or more than written as Student A?

Answer 1

It will take Student B 6 hours to have written the same or more than Student A, considering Student A is currently on page 5 and Student B on page 2, with their respective writing speeds of 1/2 page and 1 page per hour.

Step-by-step explanation:

To determine the number of hours it will take for Student B to have written the same or more than Student A, we can set up an equation based on their respective writing speeds and current progress.

Let t represent the number of hours it will take. Student A's total pages written will be 5 (current pages written) + 0.5t (since they write 1/2 a page per hour).

Student B's total pages written will be 2 + 1t (as they write 1 page per hour).

We need to find t such that the pages written by both students are equal:

5 + 0.5t = 2 + 1t

To solve for t, we can subtract 0.5t from both sides and also subtract 2 from both sides:

5 - 2 = 1t - 0.5t

3 = 0.5t

t = 6 hours

Therefore, it will take Student B 6 hours to have written the same or more than Student A.