Final answer:
To find the final temperature of 10 grams of water after adding 50 calories of heat, we use the specific heat formula. With a specific heat of 1 calorie/gram°C for water, the temperature increase is 5°C, resulting in a final temperature of 15°C.
Step-by-step explanation:
To determine the final temperature of 10 grams of water when 50 calories of heat are added, we need to apply the concept of specific heat.
The specific heat of water is 1 calorie/gram°C, meaning that it takes 1 calorie to raise the temperature of 1 gram of water by 1°C.
To find the final temperature, Tfinal, we use the formula: Q = m × c × ΔT, where Q is the heat added, m is the mass of the water, c is the specific heat, and ΔT is the change in temperature.
Given that we have Q = 50 cal, m = 10 g, and c = 1 cal/g°C, we rearrange the formula to solve for the change in temperature: ΔT = Q / (m × c).
Substituting the values, we get ΔT = 50 cal / (10 g × 1 cal/g°C)
= 5°C.
Since the initial temperature of the water is 10°C, we add this change in temperature to get the final temperature:
Tfinal = 10°C + 5°C
= 15°C.