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Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation. a. X + 12 = 20 ( 12,8,20,0) b. P - 4 = 0 (4,-4,8,0) c. 2y - 3 = 7 (0,3,5,7) Plz explain ;)

User Xjedam
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1 Answer

5 votes

Answer:

(a) 8

(b) 4

(c)5

Explanation:

We are given multiple parts and we need to provide the correct answer among the given options, also we need to prove that rest of the answers are wrong.

(a). X + 12 = 20 ( 12,8,20,0)

X= 20 -12

X= 8, so only 8 is the correct answer and rest are wrong.

Proof: lets take other given options into consideration

X= 12

X+12 =12+ 24 which is wrong because X+12 is already given as 20.

similarly,

X=20

X+12 = 20+12 = 36, which is wrong because X+12 is already given as 20.

X= 0

X+12 = 0+12 = 12, which is wrong because X+12 is already given as 20.

(b). P - 4 = 0 (4,-4,8,0)

P-4 = 0

P= 4, So only 4 will give the correct answer and not the other options.

P= -4 = -4 -4 = -8, which is wrong because P-4 is is already given as 0.

similarly,

P = 8 = 8-4 = 4, which is wrong because P-4 is is already given as 0.

P = 0, 0-4 = -4 , which is wrong because P-4 is is already given as 0.

(c). 2y - 3 = 7 (0,3,5,7)

2y = 7 + 3

2y = 10

y = 5, only 5 will satisfy this given equation and rest will be wrong,

y = 0

2y-3 = 7

2(0) - 3 = 7

-3 = 7 which is not correct as LHS and RHS must be same.

similarly,

y = 3

2y-3=7

2(3) - 3 =7

6-3 = 7

3=7 which is again wrong.

y = 7

2(7) -3 =7

14-3 = 7

11=7, which is wrong.

Therefore the given options for the correct answers is verified and the wrong answers are given as the proof.

User SixSigma
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3.6k points