Question

Suppose 100 calories of heat are added to 10 grams of water. How will the temperature of the water be affected?

a) It will increase by a certain amount.
b) It will decrease by a certain amount.
c) It will remain the same.
d) The effect cannot be determined with the given information.

Answer 1

Therefore the correct answer is Option A. The temperature of the water will increase by 10 degrees Celsius.

Step-by-step explanation:

The temperature of the water will increase if 100 calories of heat are added to 10 grams of water. This is because water has a specific heat capacity of 4.18 J/g°C, which means it requires 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius. Since 1 calorie is equal to 4.18 joules, 100 calories is equivalent to 418 joules.

To calculate the increase in temperature, we can use the formula:

ΔT = Q / (m * c)

Where ΔT is the change in temperature, Q is the heat energy, m is the mass of the water, and c is the specific heat capacity of water. Plugging in the values:

ΔT = 418 J / (10 g * 4.18 J/g°C) = 10°C

Therefore, the temperature of the water will increase by 10 degrees Celsius.