Question

What volume of 12.0 M HCl solution needs to be diluted to produce 500.0 mL of 3.00 M HCl solution?

A. 0.500 L
B. 0.250 L
C. 0.125 L
D. 1.00 L
E. 2.00 L

Answer 1

To prepare 500.0 mL of a 3.00 M HCl solution from a 12.0 M HCl solution, you would need 0.125 L of the concentrated solution, based on the dilution equation M1V1 = M2V2. Therefore correct option is C

Step-by-step explanation:

To find the volume of 12.0 M HCl solution needed to produce 500.0 mL of 3.00 M HCl solution, you can use the dilution equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution.

Using this equation:

• M1 = 12.0 M (concentrated HCl)
• M2 = 3.00 M (diluted HCl)
• V2 = 500.0 mL = 0.500 L (volume of the diluted solution)

Solving for V1:

V1 = (3.00 M × 0.500 L) / 12.0 M

V1 = 1.50 / 12.0

V1 = 0.125 L

Therefore, the volume of 12.0 M HCl needed is 0.125 L, which corresponds to option C. 0.125 L.