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The height of a golf ball hit off a 128-foot hill is modeled by the function

h(t) = -8t + 16t + 120
where h(t) is the height of a ball in inches and tis time in seconds.

a) What is the maximum height of the ball after it leaves the blaster?

1 Answer

4 votes

Final answer:

The maximum height of the golf ball hit off a 128-foot hill is 128 inches, reached at the time of 1 second after being hit.

Step-by-step explanation:

To determine the maximum height of a golf ball after it is hit off a hill, we can use the given function h(t) to model the height of the ball over time.

The function provided h(t) = -8t2 + 16t + 120 is a quadratic equation which follows the standard form of at2 + bt + c where a, b, and c are constants.

In this case, the constants are a = -8, b = 16, and c = 120. The maximum height is achieved at the vertex of the parabola represented by this function.

To find the time t at which the maximum height occurs, we use the formula t = -b/2a.

Plugging our values in, we get t = -16/(2 × -8)

= 1 second.

To find the maximum height, we substitute t back into the original equation: h(1) = -8(1)2 + 16(1) + 120

= 128 inches.

Therefore, the maximum height the golf ball reaches after being hit off the hill is 128 inches.

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