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A conductor has a conductance of 50 μS. What is its resistance?

User Akin Ozer
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Final answer:

The resistance of a conductor with a conductance of 50 μS is 20,000 Ω, or 20 kΩ, calculated by taking the reciprocal of the conductance.

Step-by-step explanation:

The student asked about the relationship between conductance and resistance of a conductor. When a conductor has a conductance of 50 μS (microsiemens), its resistance can be found by taking the reciprocal of the conductance, since conductance (G) is the inverse of resistance (R) and is defined as G = 1/R. Therefore, to find the resistance (R), we use the formula R = 1/G.

In this particular case, the resistance R of a 50 μS conductor is calculated as:

  1. R = 1/G
  2. R = 1/(50 μS)
  3. R = 1/(50 × 10^-6 S)
  4. R = 20,000 Ω or 20 kΩ (ohms)

It's important to convert microsiemens to siemens by multiplying by 10^-6 when performing the calculation.

User Joseph Siefers
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