Main answer
The average age of the employees in 2003 and in 2009 based on the function a(s) = 0.295s + 53 is;
2003: 59.49 years, 2009: 61.26 years
Step-by-step explanation
To find the average age of the employees in 2003 and 2009 based on the function A(s) = 0.295s + 53, substitute the corresponding values of s into the function.
For 2003, s = 2003 - 1981 = 22 (since 1981 is the reference year).
A(22) = 0.295 * 22 + 53
= 6.49 + 53
= 59.49
So, the average age of the employees in 2003 is approximately 59.49 years.
For 2009, s = 2009 - 1981 = 28.
A(28) = 0.295 * 28 + 53
= 8.26 + 53
= 61.26
Therefore, the average age of the employees in 2009 is approximately 61.26 years.
The function A(s) given by A(s) = 0.295s+53 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let A(s) be the average age of an employee, and s be the number of years since 1981; that is, s 0 for 1981 and s 9 for 1990. What was the average age of the employees in 2003 and in 2009 based on the function a(s) = 0.295s + 53?
A) 2003: 59.635 years, 2009: 65.715 years
B) 2003: 53.295 years, 2009: 53.885 years
C) 2003: 56.885 years, 2009: 62.965 years
D) 2003: 62.965 years, 2009: 56.885 years