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Given that y = 60x+3x² - 4x³, calculate the value of x for which y has its minimum value.

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Final answer:

To find the value of x for which y has its minimum value, we need to find the vertex of the quadratic function y = 60x + 3x² - 4x³. The value of x for which y has its minimum value is 3/8.

Step-by-step explanation:

To find the value of x for which y has its minimum value, we need to find the vertex of the quadratic function

y = 60x + 3x² - 4x³.

Since the coefficient of x³ is negative (-4), the graph of the function opens downward.

The x-coordinate of the vertex can be found using the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic function.

In this case, a = -4, b = 3, and c = 60,

so x = -3/(2*(-4))

= 3/8.

Therefore, the value of x for which y has its minimum value is 3/8.

User Giovanni Lobitos
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