Final answer:
The mass of 3.75 moles of potassium phosphate (K₃PO₄) is 795 grams. This is calculated by multiplying the number of moles by the molar mass of the substance, which is 212.27 g/mol.
Step-by-step explanation:
To determine the mass of 3.75 moles of potassium phosphate (K₃PO₄), we need to calculate its molar mass by summing the atomic masses of all the atoms in one formula unit of the substance. Potassium (K) has an atomic mass of approximately 39.10 amu, phosphorus (P) has an atomic mass of approximately 30.97 amu, and oxygen (O) has an atomic mass of 16.00 amu.
The molar mass of K₃PO₄ is therefore calculated as follows:
Molar mass of K₃PO₄ = (3 × 39.10 g/mol) + (30.97 g/mol) + (4 × 16.00 g/mol)
= 117.30 g/mol + 30.97 g/mol + 64.00 g/mol
= 212.27 g/mol
Once we have the molar mass, we can calculate the mass of 3.75 moles by multiplying the number of moles by the molar mass:
Mass = moles × molar mass
Mass = 3.75 moles × 212.27 g/mol
Mass = 795.01 grams
Therefore, there are 795 grams of potassium phosphate in 3.75 moles.