Final answer:
The acceleration of the helicopter is 5 m/s² and the net force acting on it is 40,000 N. These values were calculated using the acceleration formula and Newton's second law of motion.
Step-by-step explanation:
The question asks to calculate the acceleration of an 8,000 kg helicopter that increases its speed from 0 m/s to 25 m/s in 5 seconds and the net force acting on it during this acceleration.
Step 1: Calculate the Acceleration
Acceleration is defined as the change in velocity divided by the time taken for that change. The formula for acceleration (a) is:
a = (Vf - Vi) / t
where:
- Vf is the final velocity (25 m/s)
- Vi is the initial velocity (0 m/s)
- t is the time (5 seconds)
Plugging in the values:
a = (25 m/s - 0 m/s) / 5 s
= 5 m/s²
Step 2: Calculate the Net Force
The net force is calculated using Newton's second law of motion:
F = m × a
where:
- m is the mass of the helicopter (8,000 kg)
- a is the acceleration (5 m/s²)
Plugging in the values:
F = 8,000 kg × 5 m/s²
= 40,000 N
Therefore, the helicopter's acceleration is 5 m/s² and the net force acting on it is 40,000 N.