Question

What standard form polynomial expression represents the area of the triangle

Answer 1

Since what we are presented with is an isosceles triangle, the missing side will be equal to the side provided by the exercise. Also, remember that the area of a rectangle is given by

`A_T=(b* h)/(2)`

Where,

-b: the base of the triangle.

-h: the height of the triangle.

In that sense, the area of the triangle given is

`\begin{gathered} A_T=((3g^2-6g+2)(3^g^2-6g+2))/(2) \\ A_T=(1)/(2){}\lbrack9g^4-18g^3+6g^2-18g^3+36g^2-12g+6g^2-12g+4\rbrack \\ A_T=(1)/(2)(9g^4-36g^3+48g^2-24g+4) \\ A_T=(9)/(2)g^4-18g^3+24g^2-12g+2 \end{gathered}`

The standard form polynomial expression is given by the last equation in the above process. In other words, the answer is

9/2g^4-18g^3+24g^2-12g+2