Final answer:
The average wavelength of a neon atom at 25 °C traveling at 607.1 m/s is calculated using the de Broglie wavelength formula to be 3.30 x 10^-11 meters.
Step-by-step explanation:
To find the average wavelength of a neon atom at 25 °C with an average speed of 607.1 m/s, we can use the de Broglie wavelength formula λ = h / mv, where λ is the wavelength, h is Planck's constant, m is the mass of the particle, and v is the velocity.
The mass of a neon atom is 20.1796 amu, or approximately 3.35 x 10^-26 kg when converted to kilograms.
Using the value of Planck's constant (h=6.626 x 10^-34 J s), and given v=607.1 m/s, we can calculate the de Broglie wavelength of the neon atom.
λ = h / (mv)
= 6.626 x 10^-34 J s / (3.35 x 10^-26 kg * 607.1 m/s)
= 3.30 x 10^-11 m.
Therefore, the average wavelength of a neon atom at this temperature is 3.30 x 10^-11 meters.