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How many milliliters are in a balloon containing 1230 mg of nitrogen gas at standard temperature and pressure?

A) 22.4 mL
B) 24.45 mL
C) 28.32 mL
D) 32.00 mL

1 Answer

3 votes

The amount of volume (mL) in a balloon containing 1230 mg of nitrogen gas at standard temperature and pressure is 990mL.

The amount of volume in a gas at standard temperature and pressure can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • T = temperature
  • R = gas law constant

At S.T.P, P = 1atm, T = 273K

number of moles in nitrogen gas = 1.23g ÷ 28g/mol = 0.044mol

1 × V = 0.044 × 0.0821 × 273

V = 0.99L = 990mL

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