Question

three groups of students:S (blue and green): The set of students who took a Spanish class.T (green and orange): The set of students who traveled to a Spanish-speaking country.D(red and orange): The set ofstudents who did not take a Spanish class.Each block represents one student. how many times more likley is it for a student who took spanish to have traveled to a spanish speaking country than a student who did not take spanish

Answer 1

It is 3.3 times as likely.

Explanation

From the graph, the fraction of students who traveled to a Spanish speaking country and took Spanish is:

`have\text{ traveled and took Spanish}=\frac{green\text{ blocks}}{blue\text{ and green blocks}}=(8)/(8*3)=(1)/(3)`

From the graph, the fraction of students who traveled to a Spanish speaking country and did not take Spanish is:

`have\text{ traveled and did not take Spanish =}\frac{orange\text{ blocks}}{orange\text{ and red blocks}}=(8)/(8*10)=(1)/(10)`

Then, the ratio between students who took Spanish and have traveled to a Spanish speaking country and students who did not take Spanish and have traveled to a Spanish speaking country is:

`\frac{have\text{ traveled and took Spanish}}{have\text{ traveled and did not take Spanish}}=((1)/(3))/((1)/(10))=(10)/(3)\approx3.3`