Final answer:
From the given voltage ratio and flux, we can find the number of primary and secondary turns in a single-phase transformer.
Step-by-step explanation:
The primary/secondary voltage ratio in a transformer is determined by the ratio of the number of turns in the primary coil to the number of turns in the secondary coil. In this case, the desired voltage ratio is 6000/250V. Let's assume the number of turns in the primary coil is Np, and the number of turns in the secondary coil is Ns. Since the voltage ratio is given by the formula Ns/Np, we can rearrange the formula to find the number of turns:
Ns = Np * (Vs/Vp)
where Ns is the number of turns in the secondary coil, Np is the number of turns in the primary coil, Vs is the secondary voltage (250V), and Vp is the primary voltage (6000V).
Plugging in the values, we have:
Ns = Np * (250/6000)
Given that the flux in the core is limited to 0.06 Weber, we can use Faraday's Law of electromagnetic induction to find the number of turns in the primary coil:
Vp = Np * dΦ/dt
where Vp is the primary voltage, Np is the number of turns in the primary coil, Φ is the magnetic flux, and dt is the time. Since the frequency is 50Hz, we can calculate the time as dt = 1/f = 1/50 = 0.02s.
Plugging in the values, we have 6000 = Np * (0.06/0.02).
Simplifying the equation, we find Np = 6000 * (0.02/0.06) = 2000 turns. Substituting this value into the equation Ns = Np * (250/6000), we find Ns = 2000 * (250/6000) = 83.33 turns.
Therefore, the number of primary turns is 2000 and the number of secondary turns is approximately 83.