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A 10-H coil and a 0.75-uF capacitor are in series with a

variable resistor. What must be the value of the resistance in order to draw 0.40 Amp from a 120-V, 60-Hz line?

1 Answer

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Final answer:

To calculate the resistance needed to draw 0.40 Amp from a 120-V, 60-Hz line in the RLC series circuit consisting of a 10-H coil and a 0.75-uF capacitor, we can use Ohm's Law (V = I * R) and the formula for impedance in an RLC circuit (Z = sqrt(R^2 + (Xl - Xc)^2)).

Step-by-step explanation:

To calculate the resistance needed to draw 0.40 Amp from a 120-V, 60-Hz line in the RLC series circuit consisting of a 10-H coil and a 0.75-uF capacitor, we can use Ohm's Law (V = I * R) and the formula for impedance in an RLC circuit (Z = sqrt(R^2 + (Xl - Xc)^2)).

First, we need to calculate the reactances of the inductor (Xl) and the capacitor (Xc) using the formulas Xl = 2 * pi * f * L and Xc = 1 / (2 * pi * f * C), where f is the frequency, L is the inductance, and C is the capacitance.

Then, we can substitute the values of the reactances, the voltage (V = 120 V), and the desired current (I = 0.40 A) into the equation V = I * Z to solve for the resistance (R).

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