Question

Two coils (air cores) each having 1000 turns are placed in parallel in such a way that 60% of the flux developed by one coil covers the other coil. A current of 5 A in one of the coils generates a flux of 0.05 mWb. Calculate the inductance of each coil and the mutual inductance.

Answer 1

The inductance of each coil is 0.01 Wb/A and the mutual inductance is also 0.01 Wb/A.

Step-by-step explanation:

To calculate the inductance of each coil and the mutual inductance, we need to use the formula:

M = k x sqrt(L1 x L2)

Where M is the mutual inductance, k is the coupling coefficient (which is given as 60% = 0.6), and L1 and L2 are the inductances of the two coils. In this case, the flux generated by one coil is 0.05 mWb with a current of 5 A. Using the equation for the flux of an inductor, we can find the inductance:

0.05 mWb = L1 x 5 A
L1 = 0.05 mWb / 5 A = 0.01 Wb/A

Since L1 = L2, the inductance of each coil is 0.01 Wb/A. Substituting the values into the mutual inductance equation:

M = 0.6 x sqrt(0.01 Wb/A x 0.01 Wb/A) = 0.01 Wb/A